mirror of https://github.com/coqui-ai/TTS.git
107 lines
3.7 KiB
Python
107 lines
3.7 KiB
Python
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#!/usr/bin/env python3
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# -*- coding: utf-8 -*-
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# Licensed under WTFPL or the Unlicense or CC0.
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# This uses Python 3, but it's easy to port to Python 2 by changing
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# strings to u'xx'.
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import re
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import itertools
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def _num2chinese(num :str, big=False, simp=True, o=False, twoalt=False):
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"""
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Converts numbers to Chinese representations.
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`big` : use financial characters.
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`simp` : use simplified characters instead of traditional characters.
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`o` : use 〇 for zero.
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`twoalt`: use 两/兩 for two when appropriate.
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Note that `o` and `twoalt` is ignored when `big` is used,
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and `twoalt` is ignored when `o` is used for formal representations.
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"""
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# check num first
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nd = str(num)
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if abs(float(nd)) >= 1e48:
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raise ValueError('number out of range')
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elif 'e' in nd:
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raise ValueError('scientific notation is not supported')
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c_symbol = '正负点' if simp else '正負點'
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if o: # formal
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twoalt = False
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if big:
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c_basic = '零壹贰叁肆伍陆柒捌玖' if simp else '零壹貳參肆伍陸柒捌玖'
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c_unit1 = '拾佰仟'
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c_twoalt = '贰' if simp else '貳'
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else:
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c_basic = '〇一二三四五六七八九' if o else '零一二三四五六七八九'
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c_unit1 = '十百千'
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if twoalt:
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c_twoalt = '两' if simp else '兩'
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else:
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c_twoalt = '二'
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c_unit2 = '万亿兆京垓秭穰沟涧正载' if simp else '萬億兆京垓秭穰溝澗正載'
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revuniq = lambda l: ''.join(k for k, g in itertools.groupby(reversed(l)))
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nd = str(num)
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result = []
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if nd[0] == '+':
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result.append(c_symbol[0])
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elif nd[0] == '-':
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result.append(c_symbol[1])
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if '.' in nd:
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integer, remainder = nd.lstrip('+-').split('.')
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else:
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integer, remainder = nd.lstrip('+-'), None
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if int(integer):
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splitted = [integer[max(i - 4, 0):i]
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for i in range(len(integer), 0, -4)]
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intresult = []
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for nu, unit in enumerate(splitted):
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# special cases
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if int(unit) == 0: # 0000
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intresult.append(c_basic[0])
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continue
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elif nu > 0 and int(unit) == 2: # 0002
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intresult.append(c_twoalt + c_unit2[nu - 1])
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continue
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ulist = []
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unit = unit.zfill(4)
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for nc, ch in enumerate(reversed(unit)):
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if ch == '0':
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if ulist: # ???0
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ulist.append(c_basic[0])
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elif nc == 0:
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ulist.append(c_basic[int(ch)])
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elif nc == 1 and ch == '1' and unit[1] == '0':
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# special case for tens
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# edit the 'elif' if you don't like
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# 十四, 三千零十四, 三千三百一十四
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ulist.append(c_unit1[0])
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elif nc > 1 and ch == '2':
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ulist.append(c_twoalt + c_unit1[nc - 1])
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else:
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ulist.append(c_basic[int(ch)] + c_unit1[nc - 1])
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ustr = revuniq(ulist)
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if nu == 0:
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intresult.append(ustr)
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else:
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intresult.append(ustr + c_unit2[nu - 1])
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result.append(revuniq(intresult).strip(c_basic[0]))
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else:
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result.append(c_basic[0])
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if remainder:
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result.append(c_symbol[2])
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result.append(''.join(c_basic[int(ch)] for ch in remainder))
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return ''.join(result)
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def _number_replace(match : re.Match):
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match_str: str = match.group()
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return _num2chinese(match_str)
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def replace_numbers_to_characters_in_text(text : str):
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text = re.sub(r'[0-9]+', _number_replace, text)
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return text |